22. No of permutations with n numbers. (1/(n+1)2ncn).
23. A string with a’s and b’s and with one special character ‘x’. Find out whether its palindrome or not.
24. Implement queue by stack with enque and deque of order O(1);
25. Convert infix expression to postfix.
23. A string with a’s and b’s and with one special character ‘x’. Find out whether its palindrome or not.
24. Implement queue by stack with enque and deque of order O(1);
25. Convert infix expression to postfix.
22. No of permutations with n numbers. (1/(n+1)2ncn).
ReplyDeletea) No of permutations are 1/(n+1) (2n)cn.
b) No of stack permutation possible.
c) No of binary trees possible with n nodes.
d) No of ways to parenthesise with n data element.
23. A string with a’s and b’s and with one special character ‘x’. Find out whether its palindrome or not.
a) Take two pointer one from start and another from end. Start comparing till pointers don’t cross each other.
24. Implement queue by stack with enque and deque of order O(1);
Pop all the element and push in second stack2. The top2 will point to the beginning of
Deque and top1 will be at end. Maintain size1 and size2 for the bottom removing with both the cases.
Add at beg: push in stack2, size1 and size2 incremented.
Add at end: push in stack1, size1 and size2 incremented.
Delete at beg: pop in stack2 and decrement size1 and size2.
Delete at end: pop in stack2 and decrement size1 and size2.
25. Convert infix expression to postfix.
While ( ch )
{
If ( ch is alphanumeric ) push (ch);
If ( ch is ‘)’ ) pop from operatorstack and push(ch);
If ( ch is operator) pushoperator(ch);
}