Skip to main content

Answer for Stack Q

22. No of permutations with n numbers. (1/(n+1)2ncn).
a) No of permutations are 1/(n+1) (2n)cn.
b) No of stack permutation possible.
c) No of binary trees possible with n nodes.
d) No of ways to parenthesise with n data element.

23. A string with a’s and b’s and with one special character ‘x’. Find out whether its palindrome or not.
a) Take two pointer one from start and another from end. Start comparing till pointers don’t cross each other.

24. Implement queue by stack with enque and deque of order O(1);
Pop all the element and push in second stack2. The top2 will point to the beginning of
Deque and top1 will be at end. Maintain size1 and size2 for the bottom removing with both the cases.
Add at beg: push in stack2, size1 and size2 incremented.
Add at end: push in stack1, size1 and size2 incremented.
Delete at beg: pop in stack2 and decrement size1 and size2.
Delete at end: pop in stack2 and decrement size1 and size2.

25. Convert infix expression to postfix.
While ( ch )
{
If ( ch is alphanumeric ) push (ch);
If ( ch is ‘)’ ) pop from operatorstack and push(ch);
If ( ch is operator) pushoperator(ch);
}

Comments

Popular posts from this blog

Car Parking Problem

There is n parking slots and n-1 car already parked. Lets say car parked with initial arrangement and we want to make the car to be parked to some other arrangement. Lets say n = 5, inital = free, 3, 4, 1, 2 desired = 1, free, 2, 4 ,3 Give an algorithm with minimum steps needed to get desired arrangement. Told by one of my friend and after a lot of search i really got a nice solution. I will post solution in comment part

JDBC connection factory

  Class ConnectionManager {   Queue<Connection> availableConnection;   List <Connection> allotedConnection; ConnectionManager( Integer noOfConnections, ConnectionPoperties props ) {     //Create the no of connection objects and assign to avaialbleConnection } Conection getConnection() {     syncronized( this.class) { if (availableConnection.isEmpty() ) {          throw ConnectionExhausted();       }       conn = availableCOnnection.poll();       alottledConectiion.add(conn); } return conn; } synchronized Conection releaseConnection(Connection conn) {        alottedconnection.remove(conn);    avaialbleConection.add(conn); }

Median of Five Numbers

U have 5 NOs , X1,X2,X3,X4,X5 With minimum no. of comparisons we have to find a median. SWAP(X,Y) function is available to u . I have a answer of six comparisons and eight swaps....wait for people to find out by themselves.