Skip to main content

JAVA CLASSLOADER- Types, usages.

JVM loads library and classes dynamically only. Its on demand only.
A Class will be loaded only when needed and only once.

There can be system supported class loader and user supplied class loader.
When JVM starts it loads three type of class loader
1. Bootstrap loader - When system boots. Loads from jre_home/lib/
2. External class loader - Loads from jre_home/lib/ext.
3. System Class loader - Loads classes from system property CLASSPATH.


Besides this user can provide their own class loader which is pretty easy to implement in Java.
User supplied loader will work in conjunction with other loader i.e. system loader too.

Some of the examples are:

1. Load library at runtime from http resources. Example scripting classes, bean classes.
2. Can load encrypted class files with new class loader.
3. Modify the byte code.

Application Container loads classes from deployed WAR or EAR files using a tree of class loaders.

Comments

Popular posts from this blog

Car Parking Problem

There is n parking slots and n-1 car already parked. Lets say car parked with initial arrangement and we want to make the car to be parked to some other arrangement. Lets say n = 5, inital = free, 3, 4, 1, 2 desired = 1, free, 2, 4 ,3 Give an algorithm with minimum steps needed to get desired arrangement. Told by one of my friend and after a lot of search i really got a nice solution. I will post solution in comment part

DEShaw Interview Questions

ther are N numbers frm 1 to N and starting from index 1 we will keep deleting every alternate going in cyclic order with array. Only one element will be left at the end. Tell us the index of element in array we started. e.g. there are 5 nums 1 2 3 4 5 then after 1st iteration 1 3 5 will be remained. .. then 1 will be next to be elliminated and then 5 3 will remain alone... give sum efficient algorithm to calculate which numer will remain at the end Answer: 2*(n-2^p)+1 where p=floor(log2 n)

[Tree]..Is parent or grandparent?

There are two nodes given in a tree(not binary tree). Find whether one node is parent/grand parent of other. order should be O(1). tag root as 0 , tag left child as 00 , right child as 01. left child's left child as 000 , left's child's right child as 001 ... and so on. now let input be tags t1 and t2 if( (t1 == (t2>>1)) || (t2==(t1>>1))) return child parent relationship if( (t1 == (t2>>2)) || (t2==(t1>>2))) return child grand-parent relationship ... This solution can take a lot of space as the three grows. We can tag the node by number .. Root -0 1 -2-3-4 SO given two node get their tags.. Get Max of both t1, t2. Go for parent of that node if other node then return or check for parent of parent and check again for other node. With 2^32 value avaialable for indexing ..u wont run out of values.