Skip to main content

Is Binary Tree?

Given a binary tree,write an algorithm to find if the tree is a binary search tree or not.

Simple Recursive call is good..

int check_tree(bst *node)
{
if(!node)
return TRUE;
if(node->left!=NULL && node->infoleft))
return(false);
if(node->right!=NULL && node->inforight))
return(false);
if(!check_tree(node->left) || !check_tree(node->right))
return(false);
return(true);
}

I have already posted better algorithm in my tree sections earlier.
Set Min and Max to INT_MIN and INT_MAX
bool IsBst( node *root, int min, int max)
{
if (!root) return true;
if ( !isBst( root->left,min,root->info) return false;
if ( !isBst(root->right,root->info,max) return false;
return true;
}

Comments

Popular posts from this blog

Car Parking Problem

There is n parking slots and n-1 car already parked. Lets say car parked with initial arrangement and we want to make the car to be parked to some other arrangement. Lets say n = 5, inital = free, 3, 4, 1, 2 desired = 1, free, 2, 4 ,3 Give an algorithm with minimum steps needed to get desired arrangement. Told by one of my friend and after a lot of search i really got a nice solution. I will post solution in comment part

Median of Five Numbers

U have 5 NOs , X1,X2,X3,X4,X5 With minimum no. of comparisons we have to find a median. SWAP(X,Y) function is available to u . I have a answer of six comparisons and eight swaps....wait for people to find out by themselves.

Consistent Hashing

I will try to explain consistent hashing with a real world example. Let's assume I have a restaurant with 60 tables and 5 servers (waiter). Each server is given an equal number of tables to serve. Now let's assume we have addition of a new server (waiter), so his addition will be marked in the circle and he will be receiving tables from the previous server to his distance only. Check the attached example. Assume a server (waiter) has left the organisation and we have only 4 servers now. Server3 has left the restaurant, so his table will be assigned to server 4. I am sure you have noticed the load is not equally distributed. But to make the system less prone to addition/removal we just rotate in clockwise and assign range from the previous server to present server.  To make sure load is balanced or optimally balanced we need to use virtual nodes. Check links here: http://tom-e-white.com/2007/11/consistent-hashing.html https://www.toptal.com/big-data/...